# Line slope calculator x-6y=-15

**Straight line given by points A[3; 3] and B[9; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.1667x+2.5

**Canonical form of the line equation:**x-6y+15 = 0

**Parametric form of the line equation:**

x = 6t+3

y = t+3 ; t ∈ R

**Slope:**m = 0.1667

**Slope angle of line: φ =**9°27'44″ = 0.1651 rad

**X intercept:**x

_{0}= -15

**Y intercept:**y

_{0}= q = 2.5

**Distance line from the origin:**d

_{0}= 2.466

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(6; 1)

**Normal vector: n =**(1; -6)

**Midpoint of the segment AB: M =**[6; 3.5]

**Perpendicular Bisector equation:**6x+y-39.5 = 0

**Vector OA = (3; 3) ; |OA| = 4.2426**

**Vector OB = (9; 4) ; |OB| = 9.8489**

**Scalar product OA .OB = 39**

**Angle ∠ AOB = 21°2'15″ = 0.3672 rad**